ABSTRACT
The pattern of the molecular ion (m/z 218/220, 41%:39%) indicates that there is a bromine atom in the molecule and no nitrogen. As a result of the sequential loss of 17 and 28 mass units, the peaks at m/z 201/203 and m/z 175/177 suggest we are dealing with a carboxylic acid that easily loses hydroxyl radical and carbon monoxide. In fact, the fragment after decarboxylation and loss of hydrogen bromine is the base peak of the spectrum (m/z 94). From this data, C8H11BrO2 can be proposed as the molecular formula, so it is a compound with four unsaturations.
