ABSTRACT
Since 5 2 3 dy dx
x then dy dx
x x
3 2 5
3 5
2 5
Hence, y x
dx 3 5
2 5
⎛ ⎝ ⎜⎜⎜
⎞ ⎠ ⎟⎟⎟∫
i.e. y x x
c, 3 5 5
2 which is the general solution.
Substituting the boundary conditions y 125 and x 2 to evaluate c gives:
1 2 5
6 5
4 5
c, from which, c 1.
