ABSTRACT
Since u(1)=y'; u(2)=y'+(1-a)y': u(3)=y'+(1-a)y'+(1-a)2y’; …; we can see that
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Since u(1)=y'; u(2)=y'+(1-a)y': u(3)=y'+(1-a)y'+(1-a)2y’; …; we can see that