ABSTRACT

Ck1)(b) = +bk bk+lbk+2bk+3 + bkbk+lbk+2h+3 + bkbk+tbk+2bk+3 -bkbk+l bk+2bk+3-bkbk+lbk+2bk+3-bkbk+lbk+2 bk+3·

Here (and in the sequel), the k indices are evaluated modulo four. The kth element of the collision operator, C(2), for LB2 is written