Chapter S4: Ordinary Differential Equations

Particular solutions: y = Ak, where the Ak are roots of the algebraic (transcendental) equation g(Ak) = 0.

3. g(x)y′x = f1(x)y + f0(x). Linear equation.

Solution:

y = CeF + eF ∫ e-F

f0(x) g(x) dx, where F (x) =

∫ f1(x) g(x) dx.