ABSTRACT

Problem 2. If z= f (u,v,w) and z=3u2−2v +4w3v2 find the total differential, dz

The total differential

dz = ∂z ∂u

du + ∂z ∂v

dv + ∂z ∂w

dw

∂z

∂u = 6u (i.e. v and w are kept constant)

=

(i.e. u and w are kept constant) ∂z

∂w = 12w2v2 (i.e. u and v are kept constant)

Hence

dz= 6udu+ (8vw3 − 2) dv + (12v2w2)dw

Problem 3. The pressure p, volume V and temperature T of a gas are related by pV =kT , where k is a constant. Determine the total differentials (a) dp and (b) dT in terms of p, V and T

(a) Total differential dp= ∂p ∂T

dT + ∂p ∂V

dV

Since pV =kT then p = kT V

hence ∂p ∂T

= k V

and ∂p ∂V

= −kT V 2

Thus dp = k V

dT − kT V 2

dV

Since pV = kT,k = pV T

Hence dp =

( pV T

) V

dT −

( pV T

) T

V 2 dV

i.e. dp= p T

dT − p V

dV

(b) Total differential dT = ∂T ∂p

dp+ ∂T ∂V

dV

Since pV =kT,T = pV k

hence ∂T ∂p

= V k

and ∂T ∂V

= p k

Thus dT = V k

dp+ p k

dV and substituting k= pV T

gives:

dT = V( pV T

) dp + p( pV T

) dV

i.e. dT = T p

dp+ T V

dV

Now try the

Practice Exercise 251 Further problems on the total differential (answers on page 1139)

In Problems 1 to 5, find the total differential dz

1. z= x3+ y2

2. z=2xy− cosx

3. z= x − y x + y

4. z= x ln y

5. z= xy+ √

x

y −4

6. If z= f (a,b,c) and z=2ab−3b2c+abc, find the total differential, dz

7. Given u= ln sin(xy) show that du= cot(xy)(ydx + x dy)

Sometimes it is necessary to solve problems in which different quantities have different rates of change. From equation (1), the rate of change of z, dz

dt is given by:

dz dt

= ∂z ∂u

du dt

+ ∂z ∂v

dv dt

+ ∂z ∂w

dw dt

+ ··· (2)

Problem 4. If z= f (x, y) and z=2x3 sin 2y, find the rate of change of z, correct to 4 significant figures, when x is 2 units and y is π/6 radians and when x is increasing at 4 units/s and y is decreasing at 0.5 units/s

Using equation (2), the rate of change of z,

dz dt

= ∂z ∂x

dx dt

+ ∂z ∂y

dy dt

Since z=2x3 sin2y, then

∂z

∂x = 6x2 sin2y and ∂z

∂y = 4x3 cos2y

is

and since y is decreasing at 0.5 units/s, dy dt

=−0.5

Hence dz dt

=(6x2 sin2y)(+4)+ (4x3 cos2y)(−0.5) =24x2 sin 2y − 2x3 cos2y

When x =2 units and y= π 6

radians, then dz dt

= 24(2)2 sin[2(π/6)]− 2(2)3 cos[2(π/6)] = 83.138− 8.0

Hence the rate of change of z, dz dt

=75.14units/s, correct to 4 significant figures.