ABSTRACT
Thus conductance, G=1/R and inductive susceptance, BL =−1/XL.
(g) resistance and capacitance in parallel, then
Z = (R)(−jXC ) R − jXC
( i.e.
product sum
)
and Y = 1 Z
= R − jXC−jRXC = R−jRXC
− jXC−jRXC i.e. Y = 1−jXC
+ 1 R
= ( j ) (−jXC )( j )
+ 1 R
or Y = 1 R
+ j XC
(1)
Thus conductance, G=1/R and capacitive susceptance, BC = l/XC The conclusions that may be drawn from Sections (d) to (g) above are: (i) that a series circuit is more easily represented
by an impedance, (ii) that a parallel circuit is often more eas-
ily represented by an admittance especially when more than two parallel impedances are involved.
