ABSTRACT
So, the matrix is not invertible when λ ∈ 1 2 5 + 3
2 5 ,3 .
(a) By direct calculation, we get det(R) = cos2θ + sin2θ = 1.
(b) The inverse is R−1 =
1 0 0
0 cosθ sinθ
0 − sinθ cosθ
.
(c) Observe that R−1 = RT.
So, the matrix is not invertible when λ ∈ 1 2 5 + 3
2 5 ,3 .
(a) By direct calculation, we get det(R) = cos2θ + sin2θ = 1.
(b) The inverse is R−1 =
1 0 0
0 cosθ sinθ
0 − sinθ cosθ
.
(c) Observe that R−1 = RT.