ABSTRACT
L # 0 ! # # %#
2M3/# 0#% #0 ((0&((0#6 %) =# %0 !!π # ""# 0 #
/ # #%#0 % % #0 # 0 # #"0%##( #( % /*'F#$% ## #(("0"# #=# #(# %0
#"#( % &)## 0 #"#(
/ % 0 # #( #("# & ( #)&6% )& )& )& ) /# # (# % #7%# % % %%#(0#%% ( #( #( 080 0 %# # !(" #" % # %#((/ 0# #(#(# ' # !" C ( %! # #/"#&((% )%#(/! 0 #% %(% "# "" >%?# I#% # (# 6 %! #" #% #
F ( # % ## # " % ""0 % ((6 # %## 7%#! " ! # #"(% # #(% #(# # #" +% 7%6 #(# 0# 0 (# ; !#""#! 0#;#((% # %## 7%#"#( ##! "#!#(6 #* #0 ((6 # # 7%## # 0 6 #% % # #"0 # (7%#/ ##% #(#(#% 8 (#% # # ####0#"""#% ## # 0 ### 0 # # #((( (#% ##!0## ! ## > ; #(#(1% H# #=%#%/" (# "& (# ## ##( (%#)/ #(# % ## 6 0" (#
√ ! "##
$ %&'() * + , - . +) .* / * %0''#1 + + , # 1 # 2 *3%0&4 , #, , 21.%00 π # ## π , 5 " , 6, ,, ,# " # 37. # , , , , ,# , " 8 , " " " " π " # + , #π%,, " 8π
transcendental, there cannot be such a relation. Lindemann actually proved that numbers created by a more general rule were transcendental, with π the most prominent example. Hilbert’s problem was a further attempt to flesh out the realm of transcendental numbers.
