ABSTRACT
D2 +3D+ 2 = 0 (6-7) The quadratic formula quickly gets us the roots s1 = -2, s2 = -1 and the complementary solution Xc = C1e-21 + C2e-1• Repeated differentiation of the forcing function 4e-51 gives only terms of the form Ae-51 , so the method of undetermined coefficients will work. The solution xP = Ae-51 is substituted into Eq. (6-6) to give
C -21 C -t 1 -51 x=xc+Xp= 1e + 2e +3e
To find C1 and C2 we apply the initial conditions.
