ABSTRACT
Determine the temperature distribution in the wall. 116. The pipe described in Problem liS is cooled by convection on the outer
surface. Thus, the heat conduction qcond at the outer wall is equal to the heat convection qconv to the surroundings:
qcond = -kA dT = qconv = hA(T - Ta)dr
where the thermal conductivity k = 100.0 J/(s-m-K), the convective cooling coefficient h = 500.0 J/(s_m2-K), and Ta = 0.0 C is the temperature of the surroundings. Determine the temperature distribution in the wall.
