ABSTRACT
Since 2Х2(Т , 0)+ТХі(Т , 0) = ЗT ф 0, it follows that A0 Ф 0, and hence X \ ( T , A0) = X 2(T, A0) = Хз(Т, A0) = 0. But this is impossible. Thus, if 5Ş, ф ST , then 5 (5 ^ ) П jB(S?t ) = 0-From this and from the relation В(ат) C В and the continuity of В(ат) we conclude that there exists δ?τ such that В{ат) = 0 .
