ABSTRACT

Proposition 4.1. Let k ≥ 2 be an integer and let m be a positive integer. Then m is a kth power if and only if all the exponents in the

) the exponents 6 and 3 are multiples of 3, but is not a sixth power since the exponent 3 is not a multiple of 6. Similarly, 2000 = 2453 is not a cube since the exponent 4 is not a multiple of 3.