ABSTRACT
Now proceed to the row or column containing p 11 and its successor. Re-
place the entries using Lemma 2.18 as follows. Continue to assume that the path begins with a row; p
for
Case 1 ar2 = pr2 1-II12 = prs 1 – p12
r 1.
Now proceed to the row or column containing p 11 and its successor. Re-
place the entries using Lemma 2.18 as follows. Continue to assume that the path begins with a row; p
for
Case 1 ar2 = pr2 1-II12 = prs 1 – p12
r 1.