ABSTRACT

Solutions: y1(x) = 0, y2(x) = – 2λ + 1

A(b2λ+1 – a2λ+1) x λ .

2. y(x) + A ∫ b

xλtµy2(t) dt = 0.

Solutions: y1(x) = 0, y2(x) = – 2λ + µ + 1

A(b2λ+µ+1 – a2λ+µ+1) x λ .

3. y(x) + A ∫ b

e-λxy2(t) dt = 0.

Solutions: y1(x) = 0, y2(x) = 2λ

A(e-2λb – e-2λa) e –λx

.