On the Solutions of a Family of Sextic Thue Equations

We consider the Thue equation (1.1) https://www.w3.org/1998/Math/MathML"> F n ( x , y ) = x 6 − 2 A n x 5 y − 5 ( A n + 3 ) x 4 y 2 − 20 x 3 y 3 + 5 A n x 2 y 4 + 2 ( A n + 3 ) x y 5 + y 6 = 1 https://s3-euw1-ap-pe-df-pch-content-public-p.s3.eu-west-1.amazonaws.com/9780138747022/abb99e87-ffb7-4196-a4c4-acb0033e3d6a/content/eq3263.tif" xmlns:xlink="https://www.w3.org/1999/xlink"/>