ABSTRACT
Ps Ps(2.5), and determine the deflated polynomial P4(x) obtained by removing the factor (x - 2).
Evaluating Ps(2.5) by nested multiplication using Eq. (4.19) yields
bs = 1.0 b4 = -15.0 + 2.5(1.0) = -12.50 b3 = 85.0 + 2.5(-12.5) = 53.750 b2 = -225.0 + 2.5(53.750) = -90.6250 b l = 274.0 + 2.5(-90.6250) = 47.43750 bo = -120.0+2.5(47.43750) = -1.406250
(4.29.5) (4.29.4) (4.29.3) (4.29.2) (4.29.1) (4.29.0)
Thus, Ps(2.50) = bo = -1.406250. This result can be verified by direct evaluation of Eq. (4.28) with x = 2.5.
