ABSTRACT
Let's calculate the mass of water in the container at this condition. The density of water is p = 1.0g/cm3. Due to axial symmetry in the geometry of the container and the height distribution, the mass in the container can be expressed in cylindrical coordinates as
J JR JR[ (z2 - Z,)?]m = dm = 0 pz(r)(2nr dr) = 2np 0 z, + R2 which has the exact integral
(6.103)
(6.104)
Substituting the specified values of p, R, z" and Z2 into Eq. (6.104) yields m = 1500ng = 4712.388980 g.
