ABSTRACT
The solution of Eq. (20.4) gives the depth Do. The method of trial and error is generally adopted to solve this equation. The minimum depth of embedment D with a factor of safety equal to 1 is therefore
D =Do + Yo (20.5) A minimum factor of safety of 1.5 to 2 may be obtained by increasing the minimum depth D
by 20 to 40 percent.
