ABSTRACT

While at elevated temperatures, the mechanical properties of steel are obtained from

and

in which E0 and σ0 are the modulus of elasticity and yield strength of steel material at ambient state.

3 THEORETICAL FORMULATION

The normal strain at a typical steel cross-section can be represented by

The alternative forms of Eq. (6) are

In Eqs. (6) and (7) y¯ is the location of the elastic centroid of the steel section below the local reference level,which is assumed to be coincident with the top fibre of the steel cross-section, yn is the location of the neutral fibre, εm, εe and εθ are the appropriate membrane, mechanical and thermal strains which are obtained from

For a given cross-section , the magnitude of the total axial force and internal bending moment can be obtained from

in which the subscripts “e” and “pi” indicate the internal actions which act on the elastic part (e) and on each of the two plastic parts (p) of the cross-section, respectively and are determined from

Substituting Eqs. (1) and (7) into Equation (11) leads to

and ωA, ωB and ωI depend on the mechanical properties of the steel material. Equation (12) can then be rearranged so that the curvature κ at a cross-section is written as a function of the internal actions in the form

Using the equilibrium of the steel element in its deformed configuration, the magnitude of the internal bending moment M int is written as a function of bending moment, shear force and axial force at the left side of the element such that

In Eq. (14) f id is the total inertia and damping forces which is given by

The relationship between the slopes at the ends of the element can be numerically found by integration of the curvature in Eq. (13) so that

Similarly, the difference in the deflections at two ends of element can be determined from Eq. (16) such that

Using Eqs. (7) and (8) the relationship between the axial deformations at the two ends of the steel element can be expressed as

At the end of the member,

For this boundary value problem Eqs. (16) to (18) leads to a system of three equations which must be solved simultaneously for M 0, R0 and N 0; this is done herein using the mathematical package MAPLE.