ABSTRACT
Proof : First note that (3 < 1 , and so by Lemma 4. 1 , lim sup Yn � ( a
(3) ' n-too e 1 -
But the hypothesis (3 < e - a
1 is equivalent to a + (3 < e ( l - (3) , and so e +
I . a a 1m sup Yn � ( (3) < --(3 ' n-too e 1 - a +
Lemma 4.15 Suppose
I = (0, a : (3 ) . Then
e - a that a + (3 > 1 and (3 < -- . e + 1
Y E I.
