ABSTRACT
Notice that g has no zeros in D and is analytic in D. Also, by expanding the factor (ζ−z)− 12 of g in a binomial series, we have that
g(z) = (ζn − rn
ζ
k
)(z ζ
and, therefore, that
p(z) = (ζn − rn
ζ
k
)(1 ζ
)k Ln−1(zk)
= (ζn − rn
ζ
(r z
k
)(1 ζ
)k zk.
