ABSTRACT
Both H(s) and T(s) should be examined for realizability [1] before proceeding. If the summation of even-order terms of P(s) is M1(s) and the summation of odd-order terms of P(s)
is N1(s), then
(13.4)
Similarly,
(13.5)
For a one-port network the driving-point impedance is synthesized by [1]
(13.6)
or
(13.7)
For a two-port network [1], if P(s) is even, the transadmittance is
(13.8)
the open-circuit transfer admittance is
(13.9)
and the open-circuit output admittance is
(13.10)
If P(s) is odd,
(13.11)
(13.12)
and
(13.13)
P s M s N s( ) = ( ) + ( )1 1
Q s M s N s( ) = ( ) + ( )2 2
Z s N s
M s ( ) = ( )( )
Z s M s
N s ( ) = ( )( )
y P s N s
M s N s21 2
( ) ( ) + ( ) ( )[ ]
y P s
N s21 2 =
( ) ( )
y M s
= ( ) ( )
y P s N s
M s N s21 2
( ) ( ) + ( ) ( )[ ]
y P s
M s21 2 =
( ) ( )
y N s
= ( ) ( )
In both cases,
(13.14)
where n is the current-ratio transfer function from port 1 to port 2. From these y-or z-parameters, the required values for the network components, i.e., L, C, and R, can be determined [1].
