+ anzn + · · ·

Since p -1< q we have p(U) ct. q(U). Thus there exists 0 < r0 < 1 for which

p(Ur 0

z0 E dUr0 such that p(z0 ) E dq(U). This implies that there exists

I. Two Special Cases

responding to q (V) being a disk and q (V) being a half-plane.