## ABSTRACT

We now expand each term on the right-hand side in similar fashion, where

now it is in terms of the variable y/y0/k . As a result we obtain

f (x0, y0k)f (x0, y0)k @f

@x

k2

@2f

@x2

. . . ,

@f

@x

@f

@x

k

@2f

@x @x

k2

@3f

@2y @x

. . . ,

@2f

@x2

@2f

@x2

k

@3f

@y @x2

. . . ,

ing together derivatives of the same order, gives

f (x0h, y0k)f (x0, y0)

h

@f

@x

k @f

@y

h2 @2f

@x2

2hk

@2f

@x @y

k2 @2f

@y2

. . .