ABSTRACT
We now expand each term on the right-hand side in similar fashion, where
now it is in terms of the variable y/y0/k . As a result we obtain
f (x0, y0k)f (x0, y0)k @f
@x
k2
@2f
@x2
. . . ,
@f
@x
@f
@x
k
@2f
@x @x
k2
@3f
@2y @x
. . . ,
@2f
@x2
@2f
@x2
k
@3f
@y @x2
. . . ,
ing together derivatives of the same order, gives
f (x0h, y0k)f (x0, y0)
h
@f
@x
k @f
@y
h2 @2f
@x2
2hk
@2f
@x @y
k2 @2f
@y2
. . .
