ABSTRACT

∫ 0 1 f ( x ) d x , $ \int_{0}^{1} f(x)dx, $ https://s3-euw1-ap-pe-df-pch-content-public-p.s3.eu-west-1.amazonaws.com/9781315315089/a42df629-db93-4a2b-bdb7-991074d3ccb1/content/inline-math5_1.tif"/> ∫ 0 π sin x d x , $ \int_{0}^{\pi } {\text{sin }}\,x\,dx, $ https://s3-euw1-ap-pe-df-pch-content-public-p.s3.eu-west-1.amazonaws.com/9781315315089/a42df629-db93-4a2b-bdb7-991074d3ccb1/content/inline-math5_2.tif"/> and ∫ 1 5 x 2 d x = x 3 3 1 5 = 124 3 $ \left. {\int_{1}^{5} x^{2} dx = \frac{{x^{3} }}{3}} \right]_{1}^{5} = \frac{124}{3} $ https://s3-euw1-ap-pe-df-pch-content-public-p.s3.eu-west-1.amazonaws.com/9781315315089/a42df629-db93-4a2b-bdb7-991074d3ccb1/content/inline-math5_3.tif"/>